六、英语附加题(本题型共2题,每题5分,共10分。要求用英文解答,列出计算步骤,每步骤运算得数精确到小数点后两位。在答题卷上解答,答案写在试题卷上无效。) 9,CC1f
1、In 2007,M Corporation paid dividends totaling $3 million on net income of $15 million.2007 was a normal year, and for the past five years, earnings have grown at a constant rate of 10 percent. However,earnings are expected to jump to $18 million in 2008,and the firm expects to have $12 million investment opportunities in 2009.It is predicted that M will not be able to maintain the 2008 level of earnings growth in the future----the high 2008 earnings level is attributable to an exceptionally profitable new product line introduced in that year----and the company will return to its previous 10 percent growth rate. M’s target debt ratio is 40 percent in 2007, which will be continued in the future. >ULp!
Calculate M’s expected dividends for 2008 if it follows each of the following policies: x["
A. Its 2008 dividend payment is set to make dividends grow at the long-run growth rate in earnings. )g_zPt
B. It continues the 2007 dividend payout ratio. bf/loMtD
C. It uses a residual policy with all distributions in the form of dividends. CaBS0'
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D. It employs a regular-dividend-plus-extras policy, with the regular dividend being based on the long-run growth rate and the extra dividend being set according to the residual policy(Indicate the regular dividend and the extra dividend separately). (02(:;1
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Answer:
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A: long-run growth rate I >Q,]S1h
3*(1+10%) =3.3 million Ai18]QD-
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B: target payout ratio GTl (i*
Target payout ratio=3/15=20% T(^8ki
Dividend of 2008=18*2%=3.6 million 5Suc#0y
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C: residual dividend approach 1C=P #MU`
Retained earnings=total new investment*(1-debt ratio) {+9\o ~
=12*(1-40%) lG>e6[Wc
=7.2 million z
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Residual dividend=18-7.2=10.8 million
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D: regular-dividend-plus-extra dividend approach (according to the residual policy) S=SncMO nE
Regular dividend=3*(1+10%) =3.3 million \|`Pul$
Extra dividend=residual dividend –regular dividend $ n[7
=10.8-3.3 *%'7~58ObS
=7.5 million g8A{aHb1}
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2. N Company manufactures a kind of product used throughout the machinery industry. The standard price of the materials for the products is $6 per kilogram; the standard quantity of materials allowed per unit is 1.5 kilograms. During July, 2,000 units of the products were finished, for which 3,200 kilograms of materials were used at a total direct material cost of $18.560. >0#q!
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A. Calculate the direct material price variance for July. Indicate whether it is favorable (F) or unfavorable (U) and who is generally responsible for this variance.
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B. Calculate the direct material quantity variance for July. Indicate whether it is favorable (F) or unfavorable (U) and who is generally responsible for this variance. 3MJWC o-[
C. Calculate the total direct material cost variance for July. Indicate whether it is favorable (F) or unfavorable (U). b2%bgs
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Answer: kTc5KHJ7
Notes: 9R"N#w.U]
Actual price=18560/3200=$5.8/unit 14!a)Ijl
Actual quantity materials per unit=3200/2000=1.6 kg/unit +{ !t~BW
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1).Standard quantity * standard price=standard total cost M`pTT5r
(1.5*2000) * 6 =$18000 T)f_W
2). (Actual quantity-standard quantity) * Standard price= Efficiency variance of direct materials KVpAV$|e
(3200-3000) * 6 =$1200 -G#@BtB2+
3)Actual quantity * (actual price- standard price)= Price variance of direct materials aw%vu
3200 * (5.8 – 6) =$640 6@;L$QYY-V
4)actual quantity *actual price =actual total cost N%|Vzc
3200 * 5.8 =$18560 b(-t)5^}
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A:Price variance of direct materials=(actual price-standard price)*actual quantity bK$D lBZ
= (5.8-6)*3200 @<TZH
= $640 【F】 o+Ti$`2<O7
Price variance of $640 【F】 due to the actual price of $5.8 per kg being fewer than the standard $6 per kg. gdFoTcHgO|
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B:Efficiency variance of direct materials= (actual quantity-standard quantity)*standard price X8n/XG ~_
= (3200-3000)*6 O8~U<'=*
=$1200 【U】 _QUu'zJ
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Efficiency variance of $1200 【U】 due to the higher quantity of materials per unit of 1.6 kg/unit than the standard level of 1.5 kg/unit. @j2*.ee
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C:Total variance of direct materials=actual costs- standard cost ^'53]b:
=18560-18000 +\[![r^P
=560 【U】 #0<y0uJ(y
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