六、英语附加题(本题型共2题,每题5分,共10分。要求用英文解答,列出计算步骤,每步骤运算得数精确到小数点后两位。在答题卷上解答,答案写在试题卷上无效。) >l b9 j>
1、In 2007,M Corporation paid dividends totaling $3 million on net income of $15 million.2007 was a normal year, and for the past five years, earnings have grown at a constant rate of 10 percent. However,earnings are expected to jump to $18 million in 2008,and the firm expects to have $12 million investment opportunities in 2009.It is predicted that M will not be able to maintain the 2008 level of earnings growth in the future----the high 2008 earnings level is attributable to an exceptionally profitable new product line introduced in that year----and the company will return to its previous 10 percent growth rate. M’s target debt ratio is 40 percent in 2007, which will be continued in the future. c;,-I
Calculate M’s expected dividends for 2008 if it follows each of the following policies: sB*!Nf^y
A. Its 2008 dividend payment is set to make dividends grow at the long-run growth rate in earnings. mhMTn*9
B. It continues the 2007 dividend payout ratio. *&z!y/
C. It uses a residual policy with all distributions in the form of dividends. \Ez&?yb/
D. It employs a regular-dividend-plus-extras policy, with the regular dividend being based on the long-run growth rate and the extra dividend being set according to the residual policy(Indicate the regular dividend and the extra dividend separately). U
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Answer: K1=j7
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A: long-run growth rate o?d`o$
3*(1+10%) =3.3 million x9o(q`N
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B: target payout ratio Y
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Target payout ratio=3/15=20% _n0NE0
Dividend of 2008=18*2%=3.6 million K}DrJ/s
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C: residual dividend approach R_=fH\c;
Retained earnings=total new investment*(1-debt ratio) SAU` u]E
=12*(1-40%) w0O(>
=7.2 million q>6RO2,
Residual dividend=18-7.2=10.8 million $T_>WUiK
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D: regular-dividend-plus-extra dividend approach (according to the residual policy) <OrQbrWQa
Regular dividend=3*(1+10%) =3.3 million A>frf[fAW
Extra dividend=residual dividend –regular dividend \D-X
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=10.8-3.3 T5-Yqz
=7.5 million ~ %Ij5PD
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2. N Company manufactures a kind of product used throughout the machinery industry. The standard price of the materials for the products is $6 per kilogram; the standard quantity of materials allowed per unit is 1.5 kilograms. During July, 2,000 units of the products were finished, for which 3,200 kilograms of materials were used at a total direct material cost of $18.560. n0)y|B#
A. Calculate the direct material price variance for July. Indicate whether it is favorable (F) or unfavorable (U) and who is generally responsible for this variance. }((P)\s
B. Calculate the direct material quantity variance for July. Indicate whether it is favorable (F) or unfavorable (U) and who is generally responsible for this variance. oz%{D@CF
C. Calculate the total direct material cost variance for July. Indicate whether it is favorable (F) or unfavorable (U). M}`T-"qf
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Answer: wjTW{Bg~G
Notes: (ylZ[M&B:
Actual price=18560/3200=$5.8/unit lpjby[S
Actual quantity materials per unit=3200/2000=1.6 kg/unit 94?/Rhs5
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1).Standard quantity * standard price=standard total cost _z\qtl~3
(1.5*2000) * 6 =$18000 @cQ
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2). (Actual quantity-standard quantity) * Standard price= Efficiency variance of direct materials !FQS9SoO9
(3200-3000) * 6 =$1200 ~ymSsoD^
3)Actual quantity * (actual price- standard price)= Price variance of direct materials O4!!*0(+91
3200 * (5.8 – 6) =$640 ?z3|^oU~d
4)actual quantity *actual price =actual total cost yQq|!'MK k
3200 * 5.8 =$18560 2gW+&5;4
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A:Price variance of direct materials=(actual price-standard price)*actual quantity U%K gLg#
= (5.8-6)*3200 xv7nChB
= $640 【F】 A{wk$`vH
Price variance of $640 【F】 due to the actual price of $5.8 per kg being fewer than the standard $6 per kg. 0IQ|`C.
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B:Efficiency variance of direct materials= (actual quantity-standard quantity)*standard price b~?3HY:t~K
= (3200-3000)*6 i x_a
=$1200 【U】 zX8{(
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Efficiency variance of $1200 【U】 due to the higher quantity of materials per unit of 1.6 kg/unit than the standard level of 1.5 kg/unit. } 7i}dyQv}
b{,vZhP-
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C:Total variance of direct materials=actual costs- standard cost kZQ$Iv+^(
=18560-18000 n*hRlL
=560 【U】 h:
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