正确答案:B 1;V_E2?V
答案解析:甲、乙、丙三种产品的边际贡献率分别为:
$j<KXR
甲:[(30-20)/30] ×100%=33.33% 7}6CUo
乙:[(25-15)/25] ×100%=40% [Z#Sj=z
丙:[(22-11)/22] ×100%=50% b:p0@ |y
各产品的销售比重为: OH
sA]7S
甲:[30×1000/(30×1000+25×5000+22×300)] ×100%=19% oZd 3H
乙:[25×5000/(30×1000+25×5000+22×300)] ×100%=77% X:;x5'|
丙:[22×300/(30×1000+25×5000+22×300)] ×100%=4% J@6j^U
加权平均边际贡献率=33.33%×19%+40%×77%+50%×4%=39.13%。